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[Technical field of the invention] It relates to the law. Hereinafter, this ultrasound is referred to as
5ASER (Saser: 5onic Alllplification by Stimulated Em lssion or Radiation = acoustic amplification
by stimulated emission of phonons). [Conventional technology and its problems] In the
conventional apparatus using ultrasonic waves, although the horn shape is devised to obtain the
directivity of the ultrasonic waves, the directivity can not be surely obtained. In particular, it is
not possible to measure spot-like measured points. OBJECTS OF THE INVENTION It is therefore
an object of the present invention to obtain very directional ultrasound. [Configuration and Effect
of the Invention] The present invention holds high purity ions in different substances at
cryogenic temperature, in a light-shielded state and 10 times or more in acoustic impedance,
applies an electric field and a magnetic field, and injects photons or electrons to bolain. Since this
polaron is made into an inverted distribution state, electrons are further injected to induce
phonons to be emitted, so that extremely high frequency, coherent ultrasonic waves can be
obtained. By using these ultrasonic waves, extremely excellent directivity characteristics can be
obtained. Equipment can be provided. DESCRIPTION OF THE PREFERRED EMBODIMENTS The
present invention will be described in detail below. FIG. 1 is a diagram showing a M axwel 1-B
oltzman distribution. FIG. 2 is a diagram showing a population inversion state of a polaron.
Figures 3 and 4 show the trajectories of polarons. FIG. 5 is a view for explaining the stimulated
emission state of phonons. FIG. 6 is a diagram showing the reflection state of phonons. FIG. 7 is a
flow chart showing a procedure for obtaining 5ASER. Gold high purity ionic crystals are obtained
by a zone melting refining method or the like in a halogen element atmosphere using silver
halide A (1CI, BrCl). Here, the energy spectrum of phonons in this crystal (particles obtained by
suspending sound waves propagating in the crystal) is derived. First, as a Hamiltonian in the
crystal lattice, "..." 15 is the momentum and space coordinates of the crystal lattice atoms. Now,
the wave function of the ground state of the crystal lattice is modified (F +,-, 1jN), Ener 'l:-? Eo
tosu. In other words, 7-positive-E. Heavy-(2) P protein = O (3). Furthermore, if the ground state is
not degenerate, positive is a real number. Here, the form of the wave function of the excited state
is assumed. Under the condition that this is orthogonal to Katsu, that is, 'Xy appearing in the
molecule of the energy expectation value (6) becomes 5-.
On the other hand, the denominator of '(6) can be written using (4). Here, PJI ? ? ? i, ?, IrA /)
? E? ? ? (island,, Fy) ? (1) is the distribution function of the crystal lattice in the ground
state (the atom of Nfllil is 1r1. иии 1 represents the probability of being in I, and n more (n <N>
atoms of the distribution function X 9 (1, j / 'u) J ? 7 "' CI%-<g Define as). In particular, there is a
probability that one atom is in point translation, but since the system is 6-spacely uniform, this is
constant regardless of the source, atomic number density, Po = N / ? (? is the system (Volume
occupied). That is, f'o (R) = B-r-n, and the distribution function P2 (/ Ri, F, 2) of two atoms is a
function of only its relative distance 1i1- /; (/ R11P2)-a sword. Denoting P (F-H-Rz) 'lo), P (Ir ")
represents the conditional probability that another atom is present at a point' when one atom is
at the origin. (?, ?) and (lf,)) can be expressed using this Po and P (11), and the equation (6) can
be obtained by setting it to 0. ?? ) Is J (F) two gods F-one (+3) w-E) = ''-three 'E K-(14) Z rr3 (r
Kl, 5 (IK) = JP (bear resistant av (IF>) It is immediately apparent that it has a solution. If the form
of 03) is used as the data, it can be seen that the sitting of (4) is an eigenfunction of the total
momentum, satisfying P additional ?0 ? ?C / 6). However, we used ? to satisfy (3). Therefore,
if ? 0, since both sitting and running are eigenfunctions of P and their eigenvalues are different,
they are orthogonal to each other, and (5) holds. The lowest energy state of This l corresponds to
the state in which one phonon exists, and ? 1 represents the energy of the phonon. Thus, 04)
represents the energy spectrum of phonons, but to look at it as a function of IK, and hence ?, it
is necessary to know what S (IK) is shaped. This phonon, ie, LO phonon (longitudinal optical
phonon) interacts with conduction electrons in the crystal lattice to cause electric polarization,
which generates a combined polaron. Now, considering S (ni) as a function including the absolute
humidity T, the polaron distribution can be obtained by the LO phonon energy MaXWellBOItZman distribution F O '? (hY) to / kBT) (II) population inversion state .
This is the first condition to get 5ASER @. Next, the physical conditions for setting T <O will be
described qualitatively. = 9-Now apply an electric field with appropriate strength and direction to
the sample to strengthen the magnetic field applied to the sample. When the magnetic field is
weak, the slow polaron is accelerated by the electric field, and the boundary having the same
energy as the L0 phonon (here, the polaron has the same energy as the L0 phonon) becomes a
circle. Next, when the magnetic field applied to the sample is strengthened, the trajectory of this
flow's motion is extremely curved. Under certain conditions, the momentum of the polaron's
trajectory before the energy of the conduction electrons reaches the circle LO In the circle LO in
momentum space, a drift of high energy polarons is obtained. That is, an inverted distribution of
polarons 10 ? with respect to energy is obtained. Next, the second condition necessary for
obtaining 5ASER, stimulated emission of phonon will be described. As in the case of the laser,
since the inverted phonon is unstable, the bowed phonon 1 in which one phonon 1 is in this
excited state is not absorbed by the polaron 1 and continues as it is. Polaron 2 and Polaron 3 are
induced to emit coherent phonon 3 and phonon 4 of equal energy by phonon 1.2, respectively.
This phonon induces emission of four coherent phonons respectively. By repeating this
process, a large number of phonons are induced to be released. Next, amplification which is a
third condition for obtaining 5ASER will be described. As described above, since this sample
(crystal) has an interface whose acoustic impedance differs by 10 times or more, the ratio of
energy to be reflected becomes and the generated phonons are mostly reflected at the interface,
and reciprocate in the crystal, Through the process, a large number of polarons induce emission
of coherent phonons. This is acoustic amplification. This collection of coherent phonons is a
coherent ultrasound having a frequency of 10 "H2 or higher. The above is the method of
obtaining coherent ultrasonic waves of 10 ? ? H 2 or more. As an application of this 5ASER, a
logic circuit having a switching time of subpicosecond level, a 5ASER fiber carrying information
of (77) bit / sea level, etc. can be considered.
Brief description of the drawings
FIG. 1 is a diagram showing the M axwel I-Boltzman distribution.
FIG. 2 is a diagram showing an inverted distribution of polarons. 3 and 4 show the trajectories of
polarons, FIG. 5 shows the stimulated emission of phonons, FIG. 6 shows the reversal of phonons,
and FIG. 7 shows the procedure for obtaining 5ASER It is a flowchart shown. Patent applicant
Tateishi Electric Co., Ltd. 13-H ?-one day state ? ░ seven-bad \ OJk sleepy
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