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```Percent Composition, Empirical and
Molecular Formulas
Courtesy www.lab-initio.com
Calculating Percentage Composition
Calculate the percentage composition
of magnesium carbonate, MgCO3.
Formula mass of magnesium carbonate:
24.31 g + 12.01 g + 3(16.00 g) = 84.32 g
пѓ¦ 24 . 31 пѓ¶
Mg пЂЅ пѓ§
пѓ· п‚· 100 пЂЅ 28 . 83 %
пѓЁ 84 . 32 пѓё
пѓ¦ 12 . 01 пѓ¶
C пЂЅпѓ§
пѓ· п‚· 100 пЂЅ 14 . 24 %
пѓЁ 84 . 32 пѓё
пѓ¦ 48 . 00 пѓ¶
O пЂЅпѓ§
пѓ· п‚· 100 пЂЅ 56 . 93 %
пѓЁ 84 . 32 пѓё
100.00
Formulas
Empirical formula: the lowest whole
number ratio of atoms in a compound.
Molecular formula: the true number
of atoms of each element in the
formula of a compound.
пЃ± molecular formula = (empirical formula)n
пЃ± molecular formula = C6H6 = (CH)6
пЃ± empirical formula = CH
Formulas
(continued)
Formulas for ionic compounds are
ALWAYS empirical (lowest whole
number ratio).
Examples:
NaCl
Al2(SO4)3
MgCl2
K2CO3
Formulas
(continued)
Formulas for molecular compounds
MIGHT be empirical (lowest whole
number ratio).
Molecular: H2O
C6H12O6
C12H22O11
Empirical: H2O
CH2O
C12H22O11
Empirical Formula Determination
1. Base calculation on 100 grams of
compound. Determine moles of each
element in 100 grams of compound.
2. Divide each value of moles by the
smallest of the values.
3. Multiply each number by an integer
to obtain all whole numbers.
Empirical Formula Determination
Adipic acid contains 49.32% C, 43.84% O,
and 6.85% H by mass. What is the
1.Treat % as mass, and convert grams
to moles
49 . 32 g carbon
1 mol carbon
пЂЅ 4 . 107 mol carbon
12 . 01 g carbon
6 . 85 g hydrogen
1 mol hydrogen
пЂЅ 6 . 78 mol hydrogen
1 . 01 g hydrogen
43 . 84 g oxygen
1 mol oxygen
16 . 00 g oxygen
пЂЅ 2 . 74 mol oxygen
Empirical Formula Determination
2. Divide each value of moles by the
smallest of the values.
Carbon:
4 . 107 mol carbon
пЂЅ 1 . 50
2 . 74 mol
Hydrogen: 6 . 78 mol hydrogen
пЂЅ 2 . 47
2 . 74 mol
Oxygen:
2 . 74 mol oxygen
2 . 74 mol
пЂЅ 1 . 50
Empirical Formula Determination
3. Multiply each number by an
integer to obtain all whole numbers.
Carbon: 1.50
x 2
3
Hydrogen: 2.50
x 2
5
Empirical formula: C3H5O2
Oxygen: 1.00
x 2
2
Finding the Molecular Formula
The empirical formula for adipic acid
is C3H5O2. The molecular mass of
adipic acid is 146 g/mol. What is the
1. Find the formula mass of C3H5O2
3(12.01 g) + 5(1.01) + 2(16.00) = 73.08 g
Finding the Molecular Formula
The empirical formula for adipic acid
is C3H5O2. The molecular mass of
adipic acid is 146 g/mol. What is the
3(12.01 g) + 5(1.01) + 2(16.00) = 73.08 g
2. Divide the molecular mass by the
mass given by the emipirical formula.
146
73
пЂЅ2
Finding the Molecular Formula
The empirical formula for adipic acid is
C3H5O2. The molecular mass of adipic acid
is 146 g/mol. What is the molecular
146
73
пЂЅ2
(C3H5O2) x 2 = C6H10O4
3. Multiply the empirical formula by this
number to get the molecular formula.
```
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